According to the ISO standard, abolish/1
can only be applied to dynamic procedures. This is odd, as for dealing
with dynamic procedures there is already retract/1
and retractall/1.
The abolish/1
predicate was introduced in DEC-10 Prolog precisely for dealing with
static procedures. In SWI-Prolog, abolish/1
works on static procedures, unless the Prolog flag iso
is set to true
.
It is advised to use retractall/1 for erasing all clauses of a dynamic predicate.
abolish(Name/Arity)
. The predicate abolish/2
conforms to the Edinburgh standard, while abolish/1
is ISO compliant.copy_predicate_clauses(From, To) :- head(From, MF:FromHead), head(To, MT:ToHead), FromHead =.. [_|Args], ToHead =.. [_|Args], forall(clause(MF:FromHead, Body), assertz(MT:ToHead, Body)). head(From, M:Head) :- strip_module(From, M, Name/Arity), functor(Head, Name, Arity).
user
and in
normal modules to redefine any system predicate. If the system
definition is redefined in module user
, the new definition
is the default definition for all sub-modules. Otherwise the
redefinition is local to the module. The system definition remains in
the module system
.
Redefining system predicate facilitates the definition of compatibility packages. Use in other contexts is discouraged.
bee
on backtracking despite the fact that bee
is already retracted.76Example by
Jan Burse.
:- dynamic insect/1. insect(ant). insect(bee). ?- ( retract(insect(I)), writeln(I), retract(insect(bee)), fail ; true ). ant ; bee.
If multiple threads start a retract on the same predicate at the same
time their notion of the entry generation is adjusted such that
they do not retract the same first clause. This implies that, if
multiple threads use once(retract(Term))
, no two threads
will retract the same clause. Note that on backtracking over retract/1,
multiple threads may retract the same clause as both threads respect the
logical update view.
resource_error(program_space)
exception. The example below
adds two facts and a rule. Note the double parentheses around the rule.
?- assertz(parent('Bob', 'Jane')). ?- assertz(female('Jane')). ?- assertz((mother(Child, Mother) :- parent(Child, Mother), female(Mother))).